Respuesta :
The average induced emf coil is 1209.5 mV.
Electromagnetic fields, or EMFs, are the combination of electric and magnetic fields. Electromagnetic radiation generates the electric and magnetic forces found in EMFs.
We have expression:
E = A(db/dt)
A = πr²
E = πr² 2(db/dt)
Where, A = Area of coil
r = radius = Diameter/2 = 12.0/2 = 6 cm = 0.06 m
db = Change in magnetic fiels = (0.65 - 0.20) T = 0.45 T
dt = time = 0.14 secs
The average induced emf in the coil can be calculated by entering in the values.
E = πr² 2(db/dt) = π(0.06) 2(0.45/0.14)
E = 1.2095 Volt = 1209.5 mV
Learn more about the Electromagnetic fields with the help of the given link:
https://brainly.com/question/17057080
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I understand that the question you are looking for is "A 12.0 cm -diameter wire coil is initially oriented so that its plane is perpendicular to a magnetic field of 0.65 T pointing up. During the course of 0.14 s , the field is changed to one of 0.20 T pointing down. What is the average induced emf in the coil?"
