During trial 5, the wire was heated from 293 k to 673 k while v was held constant at 28 v. how did the current through the circuit change during this time?

Respuesta :

The current through the circuit change during this time = I ∝ 1/ R.

Severe temperatures, cold or hot, will have adverse consequences on our wire and cable, that can motive the product to emerge as brittle and inflexible. while cables are established in conditions they are not suitable for, the cables will stiffen and crack with freezing temperatures.

As the temperature of conductor wire is increased from 273 to 673 the resistance (R), of wire increases, while the potential difference (V) is kept constant at 28V.

Therefore, current (I) will decrease as I = V/R

                                                   = I ∝ 1/ R

As R increases with increasing temperature therefore, I decreases

Hence the answer is option D.

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