The correct answer is 5.50 eV
ϕ=4.31 eV
\lambda=2.88 \cdot 10^{-7} \ \text{m}
λ=2.88⋅10
−7
m
E=5.50 \ \text{eV}
E=5.50 eV
Due to interactions with atoms that result in inelastic scattering, photoelectrons do not go very far in solids. The electrons that lose energy through inelastic collisions are seen in the spectra as steps that become more intense as they approach the high binding energy side of the core levels. Where N0 and N are the numbers of electrons before and after passing through the thickness of the sample, t, and is the angle between the surface and the plane of accretion N = N0 eV at time t =, meaning that 63% of the photoelectron have lost energy and are no longer contributing to the peak in the XPS spectra.
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