1.24 moles of Mg(OH)2
In order to completely neutralize 2.48 mol of HNO3, 1.24 moles of Mg(OH)2 are needed.
The given chemical reaction is:
Mg(OH)₂ + 2HNO₃ → Mg(NO₃)₂ + 2H₂O
It is evident from the reaction's stoichiometry that:
2 moles of HNO₃ = reacts with 1 moles of Mg(OH)₂
2.48 moles of HNO₃ = reacts with (1/2)(2.48)=1.24 moles of Mg(OH)₂
Therefore, the required moles of Mg(OH)₂ is 1.24mol.
What does stoichiometry mean?
The reaction's stoichiometry provides information about the relative moles of reactants and products that are present in the specific chemical reaction.
In just four easy stages, nearly all stoichiometric difficulties can be resolved:
To learn more about stoichiometry visit:
https://brainly.com/question/9743981
#SPJ4