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For circle c, cg = ce, cg is perpendicular to fb, and ce is perpendicular to da. what conclusion can be made? a circle with center c and chords fb and da, a segment from c to chord fb intersects chord fb at g, and a segment from c to chord da intersects chord da at e segment fb is congruent to segment da segment dc is parallel to segment fa segment gc is parallel to segment ce segment fg is congruent to segment gc

Respuesta :

Conclusion: The chords FB and DA are equidistant from the center C of a circle.

What is a circle?

A circle is a shape consisting of all points in a plane that are at a given distance from a given point, which is the center.

Now,

  • A chord is a straight line traced from one point on a circle's circumference to another point on the same circumference, avoiding the circle's center.
  • According to the question, a circle with a center C has two chords that are equidistant from the center of the circle: FB and DA.
  1. DA is located CE away from C, while FB is located CG away.
  2. However, CG = CE suggests that the two chords are equidistant from the circle's center.

Thus, the chords FB and DA are equidistant from the center C of a circle.

To learn more about circles, refer to the link: https://brainly.com/question/24375372

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