The concentration of NaOH is 0.888mol/L.
H2C4H4O6(aq)+NaOH(aq)→Na2C4H4O6(aq)+H2O(l) -------(1)
To balance the equation (1), we need to multiply NaOH and H2O by 2, The balance chemical reaction is:
H2C4H4O6(aq)+2NaOH(aq)→Na2C4H4O6(aq)+2H2O(l)
We know that the atomic mass of tartaric acid is 150.087g/mol.
Then, moles of tartaric acid =3.0g/150.087g/mol=0.0200mol
The concentration of NaOH ([NaOH]) =moles volume
⇒[NaOH]=(2×0.02mol)/45mL×10−3L.mL−1
⇒[NaOH]=0.888mol/L.
With 0.100 M NaOH, tartaric acid, H2C4H4O6, is neutralized. 45 mL of base and 3.0 g of tartaric acid react in a sample.
For instance, when hydrochloric acid (HCl) and sodium hydroxide mix, the hydroxide ion from NaOH reacts with the hydrogen ion to create water (H 2 O). The residual acid then mixes with the lingering sodium ions to create sodium chloride, an ionic molecule (NaCl).
Sodium hydroxide (NaOH) is a very hygroscopic and strongly basic organic chemical. It reacts with a variety of substances to produce quite varied outcomes and is also known as caustic soda or dye.
Learn more about molal concentration:
https://brainly.com/question/24244696
#SPJ4