A marine biologist is studying the growth of a particular species of fish. She writes the following equation to show the length of the fish, f(m), in cm, after m months:

f(m) = 3(1.09)m

Part A: When the marine biologist concluded her study, the length of the fish was approximately 5.98 cm. What is a reasonable domain to plot the growth function? (4 points)

Part B: What does the y-intercept of the graph of the function f(m) represent? (2 points)

Part C: What is the average rate of change of the function f(m) from m = 2 to m = 8, and what does it represent? (4 points)

Respuesta :

The solutions to the question are given by

a)

When the marine scientist had finished her research on the fish, the length of the specimen averaged roughly  5.98 cm. Determine a suitable domain for the growth function plot.

b)

Acceptable range for the plotting of the growth function = [0, 8].

c)

Average rate = 0.40125 centimeters

What does the y-intercept of the graph of the function f(m) represent?

Generally, the equation for is mathematically given as

a)Given: A marine researcher is examining the development of a certain kind of fish in their natural environment.

f(m) = 3(1.09)^m

When the marine scientist had finished her research on the fish, the length of the specimen averaged roughly  5.98 cm. Determine a suitable domain for the growth function plot.

b) What does it mean when the graph of the function f(m) has an intercept on the y-axis?

The function f(average )'s rate of change from the value of m = 2 to the value of m = 8

Solution:

f(m) = 3(1.09)^m

m = 0

f(0) = 3(1.09)^0

f(0)= 3 cm

The fish measured about 5.98 centimeters in length.

5.98  =3(1.09)^m

Therefore

[tex]m=\frac{ln 1.993}{ln1.09}[/tex]

m=8.00

Domain = [0 , 8]

Acceptable range for the plotting of the growth function = [0, 8].

c)

In conclusion, The y-intercept of the graph of the function f(m) represents the starting length of the fish, which is equal to 5 centimeters.

The function f(average )'s rate of change from the value of m = 1 to the value of m = 8

m = 1 => f(1) = 3(1.07)^1 = 3.21 cm

m = 8 => f(9) = 3(1.07)^8 = 5.15 cm

Change in 8 months (8 -1) is 3.21  centimeters (9.19 - 5.35).

Average rate of change of the function f(m) from m = 1 to m = 9

Average rate = (3.21/8)

Average rate = 0.40125 centimeters each calendar month

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