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Five kilograms of water in a piston cylinder arrangement are at a pressure of 100 kPa, and quality of 0.5. The water is now heated so the volume triples. The mass of the piston is such that a cylinder pressure of 200 kPa will float it. Find the final temperature and the heat transfer in the process.

Respuesta :

The final temperature and the heat transfer in the process 25961 kJ

Solution:

Take CV as the water.

m2 = m1 = m ;

m(u2 − u1) = 1Q2 − 1W2  

Process: v = constant until P = P(lift) , then P is constant.  

State 1: Two-phase  at 100 kPa

u₁ = 417.33+0.5 x 2088.72

   = 1461.7 kJ/kg,

V₁ = 0.001043+0.5 x 1.69296

   = 0.8475 m³/kg

State 2: v2, P2 <= P(lift)

V2 = 3 x 0.8475=2.5425 m³/kg;

Interpolate:

T2 = 829°C,

u2=3718.76 kJ/kg

=> V2=mv2=25.425 m³

1W2 = Plift(V2-V₁)

       =200 × 10 (2.5425 - 0.8475)

       = 3390 kJ

1Q2 = m(u2 − u₁) + 1W2

       = 10x(3718.76-1461.7)+3390

       = 25961 kJ

What is piston?

Among other related systems, pistons are found in reciprocating engines, reciprocating pumps, gas compressors, hydraulic cylinders, and pneumatic cylinders. It is the moving part that is enclosed in a cylinder and sealed off from the gas by piston rings.

To learn more about piston visit:

https://brainly.com/question/28044328

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