The correct answer is 5.78*10^-5
∆x∆v = 5.78*10^-5
∆v = 1157.08 m/s
Transverse wave motion occurs when all points on a wave oscillate along pathways that are perpendicular to the wave's advance direction. Transverse waves include surface ripples on water, seismic S (secondary) waves, and electromagnetic (e.g., radio and light) waves.
A sine or cosine curve can be used to depict a simple transverse wave because the amplitude of any point on the curve—that is, its distance from the axis—is proportional to the sine (or cosine) of an angle. The graphic depicts sine curves of varying amplitudes. These curves depict how a standing transverse wave can appear at successive (1, 2, 3, 4, and 5) time intervals.
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