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Two concentric circular loops of wire carrying current in the same direction, clockwise, initially lie in the same plane. Loop 1 has radius 1.50 cm and carries 4.00 mA. Loop 2 has radius 2.50 cm and carries 6.00 mA. Loop 2 is to be rotated about a diameter while the net magnetic field B set up by the two loops at their common center is measured\

Respuesta :

Loop 2 has a rotated through an angel of 143.8⁰.

What is Magnetic Field?

The magnetic impact on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it while the charge is travelling through a magnetic field.

r₁ = 1.5cm = 0.015m

I₁ = 4mA = 4 × 10⁻³ A

r₂ = 2.5cm = 0.025m

I₂ = 4mA = 6 × 10⁻³ A

let θ be the angel of rotation

[tex]B_{1} = \frac{u_{0} I_{1}}{2r_{1} }[/tex]

B₁ = 1.256 × 10⁻⁶ × 4 × 10⁻³/2×0.015

B₁ = 167.4 nT

[tex]B_{2} = \frac{u_{0} I_{2}}{2r_{2} }[/tex]

B₂ = 1.256 × 10⁻⁶ × 6 × 10⁻³/2×0.025

B₂ = 150.72 nT

| B₁ + B₂| = 100nT

[tex]| B_{1} + B_{2} | = \sqrt{B_{1} ^{2} + B_{2}^{2} + 2 B_{1} B_{2} cos\theta}[/tex]

on solving we get,

[tex]\theta = 143.8^{0}[/tex]

to learn more about magnetic field go to - https://brainly.com/question/24761394

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