3.2 grams of methanol are produced when 2.8 of carbon monoxide reacts with 0.50 grams of hydrogen gas
First we're going to convert the given amount of grams for each Reactant into their respective amount of moles, once we do that using their molar mass, we find that we have 0.10 moles of co and 0.496 moles of [tex]h^{2}[/tex] point so because the ratio and the balance equation is 1 to 2 ratio between the reactants. This would mean that carbon monoxide is the limiting reactant, so we're going to use the amount of moles of carbon monoxide to find the amount of grams of methanol that's going to be produced so based on the balance equation. Methanol or carbon monoxide is a 1 to 1 ratio. Where, where 1 mole of c h, 3 o h is equal to 32.04 grams, we find that the amount of methanol that's going to be produced in grams 3.2, o 4 grams of ch , 3, oh
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