5 x [tex]10^{-4}[/tex] L of reaction solution was used in the experiments.
There are two types of reaction mixtures.
0.5mg = 5 x [tex]10^{-4}[/tex] g
5 x [tex]10^{-4}[/tex] g / 102 g/mol = 5 x [tex]10^{-6}[/tex] mol
5 x [tex]10^{-6}[/tex] mol/[tex]10^{-2}[/tex] mol/L = 5 x [tex]10^{-4}[/tex] L
Hence, the approximate volume of reaction solution used in the experiments is 5 x [tex]10^{-4}[/tex] L.
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