Respuesta :

Madlad69

Answer:

2x^2-2x-12= 0

dividing by 2 both sides we get:- x^2-x-6=0

x^2-x-6 = (x-3)(x+2) = 0

so, solutions are x=3 or x= -2

Answer: x₁=3     x₂=-2.

Step-by-step explanation:

[tex]2x^2-2x-12=0\\2*x^2-2*x-2*6=0\\2*(x^2-x-6)=0\\Divide\ both\ sides\ of\ the\ equation\ by \ 2:\\x^2-x-6=0\\x^2-x-2x+2x-6=0\\x^2-3x+2x-6=0\\x*(x-3)+2*(x-3)=0\\(x-3)*(x+2)=0\\x-3=0\\x_1=3.\\x+2=0\\x_2=-2.[/tex]

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