Scenario A
Julio was given the task to produce 59 grams of iron(III) oxide, 23
F
e
2
O
3
. They had one tank of oxygen gas, 2
O
2
and 54 grams of solid iron,
F
e
. They knew that if he heated the iron in the presence of the oxygen gas, they could produce the iron(III) oxide. Since they had such little amount of iron, they decided to use as little of the iron as they could to produce the 59 grams of iron(III) oxide. Julio measured out 41 grams of iron and heated it with excess oxygen. Assume Julio's reaction went 100%. Julio was very happy that their reaction produced the 59 grams.
Scenario B
Gretchen was given the task to produce 19 grams of aluminum fluoride, 3
A
l
F
3
. They had a tank of fluorine gas, 2
F
2
, and 7 grams of solid aluminum,
A
l
. They knew that if they heated the aluminum in the presence of excess fluorine gas, they could produce the aluminum fluoride. Since Gretchen had such little amount of aluminum, they decided to use as little of aluminum as they could to produce the 19 grams of aluminum fluoride. Gretchen measured out 5 grams of aluminum and heated it with excess fluorine gas. Assume Gretchen's reaction went 100%. Gretchen was very happy their reaction produced the 19 grams.


Question #1: Which scientist did the experiment incorrectly? (1 pt)
Question #2: Explain what the scientist did incorrectly. Be sure to include the balanced equation for each scientist. Show the stoichiometry and explain in complete sentences why one experiment is wrong and the other is not. (4 pts)
Question #3: Explain specifically what the scientist should do to make the experiment correct (use numbers to support your answer). Also, include the stoichiometry to show how the scientist can make the experiment correct. (3 pts)
As you answer the questions above, use complete sentences to explain the stoichiometry you show and use proper grammar and spelling (1 pt)

Respuesta :

Based on the mole ratio of the balanced equation of the reactions;

  1. Gretchen did the experiment incorrectly
  2. Gretchen did not measure the accurate mass of aluminum required to produce 19 g of aluminum fluoride
  3. Gretchen needs to react 6.1 g of Al in excess fluorine in order to produce 19 g of AlF₃

What mass of iron(III) oxide is produced from reacting 41 g of Fe with excess oxygen?

The equation of the reaction is given below:

  • 4 Fe + 3 O₂ → 2 Fe₂O₃

Based on the reaction, mole ratio of Fe and Fe₂O₃ is 2 : 1

Moles of Fe reacted = 41/56 moles

Mass of Fe₂O₃ produced = 41/56 * 1/2 * 160 = 58.6 g

What mass of aluminum fluoride is produced from reacting 5 g of aluminum with excess fluorine?

The equation of the reaction is given below:

  • 2 Al + 3 F₂ → 2 AlF₃

Based on the reaction, mole ratio of Al and AlF₃ is 1 : 1

Moles of Al reacted = 5/27 moles

Mass of AlF₃ produced = 5/27 * 84 = 15.5 g

This is less than the required mass of AlF₃

Moles of AlF₃ in 19 g = 19/84 = 0.2262 moles

Mass of Al required = 0.2262 * 27 = 6.1 g

Based on the results above;

  1. Gretchen did the experiment incorrectly
  2. Gretchen did not measure the accurate mass of aluminum required to produce 19 g of aluminum fluoride
  3. Gretchen need to react 6.1 g of Al in excess fluorine in order to produce 19 g of AlF₃

In conclusion, the mole ratio of the reactions obtained from the equation are required to know the accurate masses of reactants required.

Learn more about mass and mole ratio at: https://brainly.com/question/16806688
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