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2. A sample of a gas is occupying a 1500 mL container at a pressure of 3.4 atm and a temperature of 25
C. If the temperature is increased to 75 °C and the volume is increased to 2000 ml, what is the new
pressure?
3. A sample of a gas is occupying a 450 mL container at a pressure of 167 kPa and a temperature of 295 K.
If the pressure is increased to 230 kPa and the volume is decreased to 400 mL, what is the new
temperature in K?
I
4. A sample of gas is occupying a 3.6 L container at a pressure of 9.2 atm and a temperature of 298 K. If
the volume is increased to 5.3 L and the pressure is decreased to 7.3 atm, what is the new
temperature?



pleaseeee hurry thank you!!

Respuesta :

Eduard22sly

2. The new pressure, given the data is 3.0 atm

3. The new temperature in K is 361 K

4. The new temperature in K is 348 K

2. How to determine the new pressure

  • Initial volume (V₁) = 1500 mL
  • Initial pressure (P₁) = 3.4 atm
  • Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
  • New temperature (T₂) = 75 °C = 75 + 273 = 348 K
  • New Volume (V₂) = 2000 mL
  • New pressure (P₂) = ?

The new pressure of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(3.4 × 1500) / 298 = (P₂ × 2000) / 348

Cross multiply

P₂ × 2000 × 298 = 3.4 × 1500 × 348

Divide both sides by 2000 × 298

P₂ = (3.4 × 1500 × 348) / (2000 × 298)

P₂ = 3.0 atm

3. How to determine the new temperature

  • Initial volume (V₁) = 450 mL
  • Initial pressure (P₁) = 167 KPa
  • Initial temperature (T₁) = 295 K
  • New pressure (P₂) = 230 KPa
  • New Volume (V₂) = 400 mL
  • New temperature (T₂) =?

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(167 × 450) / 295 = (230 × 400) / T₂

Cross multiply

T₂ × 167 × 450 = 295 × 230 × 400

Divide both sides by 167 × 450

T₂ = (295 × 230 × 400) / (167 × 450)

T₂ = 361 K

4. How to determine the new temperature

  • Initial volume (V₁) = 3.6 L
  • Initial pressure (P₁) = 9.2 atm
  • Initial temperature (T₁) = 298 K
  • New Volume (V₂) = 5.3 L
  • New pressure (P₂) = 7.3 atm
  • New temperature (T₂) =?

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(9.2 × 3.6) / 298 = (7.3 × 5.3) / T₂

Cross multiply

T₂ × 9.2 × 3.6 = 298 × 7.3 × 5.3

Divide both sides by 9.2 × 3.6

T₂ = (298 × 7.3 × 5.3) / (9.2 × 3.6)

T₂ = 348 K

Learn more about gas laws:

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