Answer:
=> 1.0 M
Explanation:
The question is asking us to find the molarity of the acid (HCl).
We have been provided with;
- 25.0 mL of 0.40 M NaOH
- 10.0 mL of HCl
We know that molarity (M) of a solution is contained in 1 L or 1000 mL or 1000 cm³.
This means that;
0.40 M is contained in 1000 mL.
X mol is contained in 25.0 mL
[tex] = \frac{25 \: \times \: 0.40}{1000} \\ = 0.01 \: moles[/tex]
These 0.01 moles is contained in 10 mL of HCl.
To find the molarity of the acid;
0.01 moles is contained in 10 mL
x mol is contained in 1000 mL
[tex]x \: mol \: = \frac{0.01 \times 1000}{10} \\ = 1.0 \: mol[/tex]
= 1.0 M
Therefore the molarity of the acid (HCl) is 1.0 M
