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It takes 5.4 kJ to vaporize 1.6 moles of substance Z. What is the molar heat of vaporization of substance Z? Give your answer in units of kJ/mol with correct significant figures.

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onyebuchinnaji

The molar heat of vaporization of substance Z is 3.375 kJ/mol.

Molar heat of vaporization of substance Z

The molar heat of vaporization of substance Z is calculated as follows;

ΔH(vap) = E/n

where;

  • E is the energy required
  • n is number of moles

ΔH(vap) = 5.4 kJ/1.6

ΔH(vap) = 3.375 kJ/mol

Thus, the molar heat of vaporization of substance Z is 3.375 kJ/mol.

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