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In a survey of 4096 adults, 733 oppose allowing transgender students to use the bathrooms of the opposite biological sex Construct a 99% confidence interval for the population proportionInterpret the results A 99% confidence interval for the population proportion is (Round to three decimal places as needed)

Respuesta :

A 99% confidence interval for the population proportion is; CI = (0.164, 0.194)

How to construct the confidence Interval?

We are given;

Sample size; n = 4096

Number that opposed transgender students; x = 733

Thus;

Proportion; p^ = x/n = 733/4096 = 0.179

Formula for confidence interval of proportions is;

CI = p^ ± z√[p^(1 - p^)/n]

The z-value for confidence level of 99% is z = 2.576

Thus;

CI = 0.179 ± 2.576√[0.179(1 - 0.179)/4096]

CI = 0.179 ± 0.015

CI = (0.164, 0.194)

Read more about Confidence Interval at; https://brainly.com/question/17097944

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