what is the length of the diagonal of the square shown below
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Answer:
7[tex]\sqrt{2}[/tex]
Step-by-step explanation:
the diagonal d divides the square into 2 right angles.
using Pythagoras' identity in one of the right triangles , then
d² = 7² + 7² = 49 + 49 = 98 ( take square root of both sides )
d = [tex]\sqrt{98}[/tex] = [tex]\sqrt{49(2)}[/tex] = [tex]\sqrt{49}[/tex] × [tex]\sqrt{2}[/tex] = 7[tex]\sqrt{2}[/tex]
Answer:
c =7√2
Step-by-step explanation:
using the Pythagorean theorem we solve the diagonal ,where the two sides are given to find the hypotenuse.
c² =a² + b²
where c is the diagonal (hypotenuse fot thr triangle)
a and b are the legs (sides)
c² =7²+7²
c²= 98
c= √98
c=√49.√2
c=7√2