The value of g(x) = 2[f(x)]² - 1 is g(x) = 8x² + 8x + 1
f(x) = 2x+1
Find
g(x) = 2[f(x)]² - 1
Hence,
g(x) = 2[2x + 1]² - 1
g(x) = 2[4x² + 4x + 1] - 1
g(x) = 8x² + 8x + 2 - 1
g(x) = 8x² + 8x + 1
learn more on function here: https://brainly.com/question/1442153
#SPJ1
