The solution to the value of x in the given equation is x = 0.00212658 or x = -0.00213958
The process of solving the unknown value of an algebraic equation involves equating the values of the unknown to the constant value.
Given that:
[tex]\mathbf{\dfrac{x^2}{0.35-x}= 1.3 \times 10^{-5} }[/tex]
[tex]\mathbf{x^2 = 1.3 \times 10^{-5} (0.35-x) }[/tex]
x² = 4.725 × 10⁻⁶ - 1.3 × 10⁻⁵x
= [tex]x^2 + 1.3\times10^{-5}x - 4.725 \times 10^{-6}[/tex]
= x²+0.000013x-0.000004725
x = 0.00212658 OR x = -0.00213958
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