A firefighter is using a hose and the flow rate of the water leaving the hose. the speed of the water leaving the hose is mathematically given as
u = 9.947 m/s
Generally, the equation for Volume flow rate is mathematically given as
(V)= (A) * (u)
Where
A= area
v=velocity
Therefore
V = A*u
V=0.032 m3/s
A=πR2
A= π*0.013
u=V/A
u=0.032/π*0.0322
u = 60.27m/s
In conclusion, the speed of the water leaving the hose
u = 60.27m/s
Read more about speed
https://brainly.com/question/7359669
#SPJ1