Answer:
9.17 atm
Explanation:
To find the new pressure of the gas, you need to use the following manipulated formula:
P₁V₁ / T₁ = P₂V₂ / T₂
In this formula,
P₁ = initial pressure (atm) P₂ = new pressure (atm)
V₁ = initial volume (L) V₂ = new volume (L)
T₁ = initial temperature (K) T₂ = new temperature (K)
Because you have been given values for all of the variables except for the new pressure, you can substitute them into the equation and simplify.
P₁ = 4.0 atm P₂ = ? atm
V₁ = 5.5 L V₂ = 2.0 L
T₁ = 300 K T₂ = 250 K
P₁V₁ / T₁ = P₂V₂ / T₂ <----- Given formula
(4.0 atm)(5.5 L) / (300 K) = P₂(2.0 L) / (250 K) <----- Insert variables
0.073333 = P₂(2.0 L) / (250 K) <----- Simplify left side
18.33333 = P₂(2.0 L) <----- Multiply both sides by 250
9.17 = P₂ <----- Divide both sides by 2.0
Answer:
=> 13.2 atm
Explanation:
From the question, we have question we have been provided with pressure, volume and temperature. Based on these variables, we are supposed to use the combined gas law formula (P1V1T1 = P2V2T2)
At location 1;
P1 = 4.0 atm
V1 = 5.5 L
T1 = 300 K.
At location 2;
P2 = ?
V2 = 2.0 L
T2 = 250 K.
We are required to determine the pressure (P2).
To begin, we make pressure (P2) the subject of in the formula:
P2 = (P1V1T1)/(V2T2) ................ eq. (i)
Then substitute the known values into the eq. (i).
P2 = (4.0 x 5.5 x 300)/(2.0 x 250) atm
= 13.2 atm.
Therefore, the pressure (P2) at location 2 is 13.2 atm.
