What is the specific heat of aluminum?
The specific heat of aluminum is 0.90J/g°C.
Given:
Heat absorbs = 677 J
Mass of the substance = 10 g
Initial temperature = 50°C
Final temperature = 125°C
Formula used:
Q = m x c x ΔT
which can also be written as,
Q = m x c x ( [tex]T_{final}[/tex] - [tex]T_{initial}[/tex] )
where,
Q = heat absorbs
m = mass of a substance
c = heat capacity of aluminum
[tex]T_{final}[/tex] = Final temperature
[tex]T_{initial}[/tex] = Initial temperature
Now, put all the values in the formula given above to get the specific heat of aluminum,
677g = (10g) x c x (125 - 50)°C
c = 0.9026 J/g°C
c = 0.90 J/g°C
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