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A radio tower, 27 m tall, is supported by two guy wires, each on opposite sides.. The angles of elevation to the top of the radio tower are 13° and 21°. To the nearest tenth of a metre, how far apart are the guy wires? Select one: a. 16.6 m b. 196.4 m c. 46.6 m d. 187.3 m

Respuesta :

The distance apart of the two guy wire is 187.7 metres

How to find the distance apart of the two wires?

The distance apart of the two wires can be found using trigonometric ratios.

Therefore,

tan ∅ = opposite / adjacent

Therefore,

tan 13 = 27 / x

x = 27 / tan 13 = 27 / 0.23086819112 = 117.391304348

tan 21 = 27 / y

y = 27 / tan 21

y = 70.338144115

Therefore,

distance apart of the guy wire = 117.391304348 + 70.338144115 = 187.728144115 = 187.7 metres

learn more on angle of elevation here: https://brainly.com/question/27883575

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