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Six bleeps equal 13 floops, and 2 floops equal 5 geebles. Based on this, 1 bleep is equal to N geebles. The integer closest to N is

A. 1
B. 2
C. 3
D. 4
E. 5

Respuesta :

semsee45

Answer:

E.  5

Step-by-step explanation:

Define the variables:

  • Let b = bleeps
  • Let f = floops
  • Let g = geebles

Given information:

  • Six bleeps equal 13 floops
  • 2 floops equal 5 geebles

Use the given information and the defined variables to create two equations:

[tex]\implies \sf 6b = 13f[/tex]

[tex]\implies \sf 2f = 5g[/tex]

Rewrite the second equation to isolate f:

[tex]\implies \sf \dfrac{2f}{2}=\dfrac{5g}{2}[/tex]

[tex]\implies \sf f = 2.5g[/tex]

Substitute this into the first equation to get an expression with just bleeps and geebles:

[tex]\implies \sf 6b = 13(2.5g)[/tex]

[tex]\implies \sf 6b = 32.5g[/tex]

Finally, divide both sides by 6 to isolate b:

[tex]\implies \sf \dfrac{6b}{6}=\dfrac{32.5g}{6}[/tex]

[tex]\implies \sf b=5.42g\;(2\:d.p.)[/tex]

Round 5.42 to the nearest integer  →  5

Therefore, N = 5

Step-by-step explanation:

Solve from the least onwards

  • 2floops are 5geebles
  • 1 floop is 5/2geebles

Then

  • 13floops are 65/2geebles

So

  • 6bleeps are 65/2geebles
  • 1 bleep is 65/12=5.4

5 is correct most

Option E

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