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You have a machine that can add exactly 46,899 pieces of candy per scoop to a giant vat and another machine that can remove exactly 13,576 pieces of candy with a different scoop from the giant vat. You have a total supply of 600,000 pieces of candy. Your giant vat starts out empty. The first machine adds scoops of candy, and then the second machine removes scoops of candy. When these two machines are done, there is only one piece of candy left in the vat. How many scoops of candy did the first machine add to the vat?

Respuesta :

The first machine has added maximum 25 scoops of candies.

Given Machine 1 can add 46899 pieces of candies in the giant vat and machine 2 can add 13576 pieces of candies in the giant vat to form total supply of 600000.

let the number of scoops added by first machine be x and number of scoops added by second machine is y.

The equation will be as under:

46899x-13576y=600000

It can be solved logically. Because other machine is removing the candies from the giant vat so the value of 13576y is minimum 600000-13576=586424. Because it atleast withdrawn 1 scoop.

So the value of 46899x is maximum 1186424 which can bewhen the number of scoops is =1186424/46899=25 approximately.

Hence the number of scoops added by first machine is maximum  25.

Learn more about equation at https://brainly.com/question/2972832

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Question contains an error as the line related to left over 1 candy should be deleted.

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