Respuesta :
This is an exercise in the General Combined Gas Law.
To start solving this exercise, we obtain the following data:
Data:
- V₁ = 4.00 l
- P₁ = 365 mmHg
- T₁ = 20 °C + 273 = 293 K
- V₂ = 2,80 l
- T₂ = 30 °C + 273 = 303 K
- P₂ = ¿?
We apply the following formula:
- P₁V₁T₂=P₂V₂T₁ ⇒ General formula
Where:
- P₁=Initial pressure
- V₁=Initial volume
- T₂=end temperature
- P₂=end pressure
- T₂=end temperature
- V₁=Initial temperature
We clear for final pressure (P2)
[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}[/tex]
We substitute our data into the formula:
[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 } \end{gathered}$}[/tex]
[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}[/tex]
Answer: The new canister pressure is 539.224 mmHg.
