the intersection points are (1, 7) and (4, 13), So the correct option is A.
To see that, we need to see when the two equations:
y = -x²+7x+1
y = 2x + 5
Can be solved simultaneously for a point (x, y). So we need to solve a system of equations.
y = -x²+7x+1
y = 2x + 5
We can rewrite:
-x²+7x+1 = y = 2x + 5
Then we can solve this for x:
-x²+7x+1 = 2x + 5
x² - 5x + 4 = 0
This is just a quadratic equation, the solutions are:
[tex]x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4*(1)*(4)} }{2} \\\\x = \frac{5 \pm 3 }{2}[/tex]
So we have two values of x:
The correspondent values of y are:
y = 2*(4) + 5 = 13
y = 2*(1) + 5 = 7
Then the intersection points are (1, 7) and (4, 13)
Then the correct option is A. The dog will catch the frisbee.
If you want to learn more about systems of equations:
https://brainly.com/question/13729904
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