Respuesta :

[tex]\\ \tt\leadsto pH=-log[H^+][/tex]

[tex]\\ \tt\leadsto -log[H^+]=13.2[/tex]

[tex]\\ \tt\leadsto log[H^+]=-13.2[/tex]

[tex]\\ \tt\leadsto [H^+]=antilog(-13.2)=6.3\times 10^{-14}M[/tex]

Oseni

The  concentration of [H3O+] will be 6.3 x [tex]10^{-14}[/tex] M

pH

Mathematically, pH = -log [H+] or -log [H3O+]

With a pH of 13.2:

      -log [H3O+] = 13.2

                     log [H3O+] = -13.2

                         [H3O+] = 6.3 x [tex]10^{-14}[/tex] M

More on pH can be found here: https://brainly.com/question/491373

#SPJ1

Otras preguntas