Line segment pq is a directed line segment beginning at p(6,-5) and ending at q(-2,4). find point r on the line segment pr that partitions it into the segments pr and pq in the ratio 3:2.

Respuesta :

Using proportions, the coordinates of point R are given as follows: R(1.2, 0.4).

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Segments pr and pq are partitioned in the ratio 3:2, hence:

[tex]PR = \frac{3}{5}PQ[/tex]

[tex]R - P = \frac{3}{5}(Q - P)[/tex]

The points are:

  • R(x,y).
  • P(6,-5).
  • Q(-2,4).

For the x-coordinate, we have that:

[tex]R - P = \frac{3}{5}(Q - P)[/tex]

[tex]x - 6 = \frac{3}{5}(-2 - 6)[/tex]

x - 6 = -4.8

x = 1.2.

For the y-coordinate, we have that:

[tex]R - P = \frac{3}{5}(Q - P)[/tex]

[tex]y + 5 = \frac{3}{5}(4 + 5)[/tex]

y + 5 = 5.4.

y = 0.4.

The coordinates are: R(1.2, 0.4).

More can be learned about proportions at https://brainly.com/question/24372153

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Answer:

Step-by-step explanation:

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