Answer:
See below
Explanation:
Vertical component of initial velocity = 200 sin 35° = 114.72 m/s
then use position formula a = 9.81 m/s^2
0 = 300 + 114.72 t - 1/2 (9.81)(t^2)
use quadratic formula with a = - 4.905 b = 114.72 c = 300
to find t = 25.76 seconds
To find the range
( horizontal distance the projectile lands from launch point)
Horizontal component of initial velocity 200 cos 35 = 163.83 m/s
( it flies horizontally at this speed for 25.76 seconds <==found above)
163.83 m/s * 25.76 s = 4220.3 meters
