The number of units of NO3 present on the product side is 6.
The given reaction is:
3Cu + 8HNO3 -----> 3Cu(NO3)2 + 2NO + 4H2O
To find:
The number of units of NO3.
Solution:
The given reaction shows that three moles of copper and eight moles of nitric acid react to produce three moles of Cu(NO3)2, two moles of NO and four moles of water.
Each molecule of Cu(NO3)2 contains two units of NO3. As the number of moles of Cu(NO3)2 produced is 3, the total units of NO3 in the product side is 3 x 2 = 6.
Therefore, the correct option is 6.
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