Using a system of equations, it is found that the average of sheep A and sheep D is of 191 pounds.
A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are the weights of the sheep, given by A, B, C and D.
Sheep A and sheep B have an average weight of 150 pounds, hence:
[tex]\frac{A + B}{2} = 150[/tex]
A + B = 300 -> B = 300 - A
Sheep B and sheep C have an average weight of 127 pounds, hence:
B + C = 254
300 - A + C = 254
C - A = -46.
A - C = 46.
C = A - 46.
Sheep C and sheep D have an average weight of 168 pounds, hence:
C + D = 336
A - 46 + D = 336.
A + D = 382.
The average weight of sheep A and sheep D in pounds is:
[tex]\frac{A + D}{2} = \frac{382}{2} = 191[/tex]
More can be learned about a system of equations at https://brainly.com/question/24342899
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