The first line is perpendicular, the second line is not perpendicular and not parallel , the third line is parallel to the above line and the forth line not parallel or perpendicular to the line.
How can the slope of the line be calculate?
The slope of the line is been given as −3x+5y=−15
Then [tex]y= \frac{3}{5x} -3[/tex], hence the slope is [tex]\frac{3}{5}[/tex]
- Slope of the first line 5x + 3y = 15 after calculation is
the slope is [tex]y= \frac{5}{-3x} +5\\\\\frac{5}{-3}[/tex]
this means that the line is perpendicular to the given line
- Slope of the second line 3x + 5y = 15 after calculation is
[tex]y= \frac{3}{-5x} +15\\\\\frac{3}{-5}[/tex]
This means that the line is not perpendicular and not parallel
- Slope of the Third line -3x + 5y = 15 can be calculated as
[tex]y= \frac{3}{5x} +15\\\\\frac{3}{5}[/tex]
This means that the line is parallel to the above line.
- Slope of the first line 3x + 5y = 15 after calculation is
[tex]y= \frac{-3}{5x} +3\\\\\frac{-3}{5}[/tex]
This means that the line is not parallel or perpendicular to the line
Learn more about slope of line at:
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