The number of people coming in during the lunch hour is 160
The complete question is in the attached image
The random numbers are given as:
18, 38, 87, 16, 56, and 5
Regroup the numbers
Number Group Probability
5, 16, 18 1 - 20 3/6
38, 56 21 - 60 2/6
56 61 - 90 1/6
Based on the individual numbers and the probability table, we have:
X 20 30 40
P 3/6 2/6 1/6
The expected value is:
[tex]E(x) = \sum xp[/tex]
This gives
E(x) = 20 * 3/6 + 30 * 2/6 * 40 * 1/6
Evaluate
E(x) = 160/6
There are six ten-minute intervals.
So, we have:
People = 6 * 160/6
Evaluate
People = 160
Hence, the number of people coming in during the lunch hour is 160
Read more about expected values at:
https://brainly.com/question/18523098
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