The amount of sucrose required will be 12.5 grams and the mass of water required will be 250 g.
5% by mass glucose solution is to be prepared. This means that 5g of glucose will be dissolved in 100 mL of water.
250g of such a solution will require 250 mL of water.
5% of 250g = 5/100 x 250 = 12.5 grams
Thus, the solution is prepared by dissolving 12.5 grams of sucrose in 250 grams (250 mL) of water.
More on stoichiometric problems can be found here: https://brainly.com/question/14465605
#SPJ1
