Answer:
D
Step-by-step explanation:
First let's list down the formulas we will be using.
Area of Quadrant = 1/4 x Area of Circle
= [tex]\frac{1}{4} \pi r^{2}[/tex]
Area of Part of a circle = (θ/360)[tex]\pi r^{2}[/tex]
First, we will find Angle QOT.
Angle QOT = 360 - 231 = 129
Area of ORST = [tex]\frac{129}{360} \pi (21)^{2} \\=\frac{6321}{40} \pi cm^{2}[/tex]
Next we know that, Q is midpoint of OR, therefore OQ = QR
and OQ = 0.5 * OR
OQ = 0.5 * 21 = 10.5cm = radius of Quadrant QOP
Area of Quadrant QOP = [tex]\frac{1}{4} \pi (10.5)^{2} \\=\frac{441}{16} \pi cm^{2}[/tex]
Lastly,
Area of Shaded Region = Area of ORST - Area of Quadrant QOP
= [tex]\frac{6321}{40} \pi -\frac{441}{16} \pi \\= 409.86cm^{2}[/tex]
Similar to the other question you asked, choose the closes answer as there might be some rounding differences. I kept it in fractions as it will ensure maximum precision.
