contestada

Consider the paragraph proof.

Given: D is the midpoint of AB, and E is the midpoint of AC.
Prove:DE = One-halfBC

On a coordinate plane, triangle A B C is cut by line segment D E. Point D is the midpoint of side A B and point E is the midpoint of side A C. Point A is at (2 b, 2 c), point E is at (a + b, c), point C is at (2 a, 0), point B is at (0, 0), and point D is at (b, c).

It is given that D is the midpoint of AB and E is the midpoint of AC. To prove that DE is half the length of BC, the distance formula, d = StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot, can be used to determine the lengths of the two segments. The length of BC can be determined with the equation BC = StartRoot (2 a minus 0) squared + (0 minus 0) squared EndRoot, which simplifies to 2a. The length of DE can be determined with the equation DE = StartRoot (a + b minus b) squared + (c minus c) squared EndRoot, which simplifies to ________. Therefore, BC is twice DE, and DE is half BC.

Which is the missing information in the proof?

a
4a
a2
4a2

Respuesta :

In the case above, the  missing information in the proof is option A: a.

What is the midpoint about?

Note that in the question;

D = mid-point of AB

E = mid-point of AC.

To  find the missing information in given proof of DE is equal to half of BC:

The coordinates of A = (2b,2c)

The coordinates of D = (b,c)

The coordinates of E  = (a+b,c)

The coordinates of  B = (0,0)

The coordinates of  C = (2a,0)

Distance formula: [tex]\sqrt{(x₂ - x₁) + (y₂ - y₁)}[/tex]

Length of BC= units[tex]\sqrt{(2a ^2 + (0 - 0)^2} = 2a units[/tex]

So BC = 2a = DE

DE = 1/2 BC

Hence in the case above, the  missing information in the proof is option A: 4.

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