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On a coordinate plane, triangle R S T has points (0, 4), (0, negative 2), and (3, negative 2).

△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).


The distance between the x-coordinates of R and T is

.

The distance between the y-coordinates of R and T is

.

R' is
from T, so the coordinates of R' are

.

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Martebi

The values gotten for the  coordinate plane are;

  • The distance between the x-coordinate of R and T is 3.
  • The distance between the y-coordinate of R and T is 6.
  • R' is (-1, 2) from T, so the coordinates of R' are (2, 0).

Why the above values?

The Reason for the obtained value is that since thee rule for the dilation of ΔRST is:

  • The vertices of the given triangle are R(0, 4), S(0, -2), T(3, -2)

Then, the distance that exist between the x-coordinate of R and T will be:

3 - 0

= 3

Then the distance between the y-coordinate of R and T will be:

4 - (-2)

= 6

Note that the location of the point R' is said to be relative to point T and as such:

The location of point R'

= (-1 + 3, 2 - 2)

= R'(2, 0)

Hence R' is (-1, 2) from T, and the coordinates of R' is (2, 0)

Therefore, The values gotten for the  coordinate plane are;

  • The distance between the x-coordinate of R and T is 3.
  • The distance between the y-coordinate of R and T is 6.
  • R' is (-1, 2) from T, so the coordinates of R' are (2, 0).

Learn more about coordinate plane from

https://brainly.com/question/10633154

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