The attached graph represents the image of the triangles
To do this, we make use of the following coordinates
A = (1, 0)
B = (5, 0)
C = (1, 6)
The lengths of the triangle are calculated using
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]AB = \sqrt{(1-5)^2 + (0 -0)^2} = 4[/tex]
[tex]BC = \sqrt{(1-5)^2 + (6 -0)^2} = 7.2[/tex]
[tex]AC = \sqrt{(1-1)^2 + (6 -0)^2} = 5[/tex]
Using the scale factor of 2, we have the image of the dilation to be:
D = (2, 0)
E = (10, 0)
F = (2, 12)
The lengths of these sides are
DE = 8
EF = 14.4
DF = 10
See attachment for the image of the triangles ABC and DEF
Read more about dilation at:
https://brainly.com/question/14245809
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