The attached graph represents the graph of [tex]\frac{(x - 2)^2}{16} - \frac{(y + 1)^2}{9} \le 1[/tex]
How to determine the graph?
The inequality is given as:
[tex]\frac{(x - 2)^2}{16} - \frac{(y + 1)^2}{9} \le 1[/tex]
The above inequality represents a conic section.
The inequality symbol <= implies that, we make use of a closed line on the graph.
Next, we plot the graph using a graphing tool
See attachment for the graph of [tex]\frac{(x - 2)^2}{16} - \frac{(y + 1)^2}{9} \le 1[/tex]
Read more about inequality at:
https://brainly.com/question/27095031
Complete question
Which graph represents [tex]\frac{(x - 2)^2}{16} = \frac{(y + 1)^2}{9}[/tex]?
