The value of x in the triangle is (a) 30√2
How to solve for x?
The complete question is in the attached image.
From the attached image of the triangle, we can see that the triangle is a right triangle, and x can be solved using the following sine function
[tex]\sin(45) = \frac{30}{x}[/tex]
Evaluate sin(45)
[tex]\frac 1{\sqrt 2} = \frac{30}{x}[/tex]
Solve for x
[tex]x = 30 * \sqrt 2[/tex]
Evaluate
[tex]x = 30 \sqrt 2[/tex]
Hence, the value of x in the triangle is (a) [tex]30 \sqrt 2[/tex]
Read more about special triangles at:
brainly.com/question/654982
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