Answer:
1. 0.35 moles NaOH
2. [tex]5.10x10^{-4}[/tex] moles [tex]H_2SO_4[/tex]
3. 505.4 g Pb
4. 1.46 g HCl (if that is wrong it's 1.5 g HCl due to sig figs)
5. [tex]3.01x10^{23}[/tex] atoms of Ag
6. [tex]2x10^{-10}[/tex] atoms of Cu
Explanation:
1. The mass of NaOH is 40g. 22.99(Na)+16(O)+1.01(H)=40 g
14 g NaOH *[tex]\frac{1 mol NaOH}{40 g NaOH}[/tex] = 0.35 moles of NaOH
2. Mass of [tex]H_{2} SO_{4} = 2(1.01)+32.06+4(16) = 98.08[/tex]
0.05 g [tex]H_2SO_4[/tex] ×[tex]\frac{1 mol H_2SO_4}{98.08g H_2SO_4} = 5.10 x10^{-4}[/tex]
3. mass of Pb = 106.4 g
4.75 moles Pb×[tex]\frac{106.4 g Pb}{1 mol Pb} =505.4 g Pb[/tex]
4. mass of HCl = 1.01 +35.45 = 36.36 g
0.04 mol HCl x [tex]\frac{36.46 g HCl}{1 mol HCl} = 1.456 = 1.5[/tex]
5. 5.00 mol Ag x[tex]\frac{6.022x10^{23} atoms }{1mol Ag} = 3.01x10^{24} atoms[/tex]
6. [tex]3x10^{-10} moles[/tex] Cu x[tex]\frac{6.022x10^{23} atoms}{1 mol Cu} = 1.8668x10^{14}= 2x10^{14}[/tex] atoms of Cu
