A ball of radius 14 has a round hole of radius 4 drilled through its center.
Find the volume of the resulting solid.
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The volume of the spherical solid resulting of the drill is of 11,226 units³.
The volume of a sphere of radius r is given as follows:
[tex]V = \frac{4\pi r^3}{3}[/tex]
In this problem, we have two spherical balls, one of radius 14 and other of radius 4, hence their volumes are given as follows:
[tex]V_1 = \frac{4\pi 14^3}{3} = 11494[/tex]
[tex]V_2 = \frac{4\pi 4^3}{3} = 268[/tex]
The volume of the resulting solid is the difference of the volumes, hence:
V = 11494 - 268 = 11,226 units³.
More can be learned about the volume of a sphere at https://brainly.com/question/25608353
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