contestada

A compound has the formula X2Fe(CN)6 ∙ 12H2O, where X is an unknown element. [3]
If the compound is 45.34% water by mass, what is the identity of element X?

Respuesta :

pstnonsonjoku

The element X from the calculation is Cs.

What is the identity of element X?

We have in the question the percentage by mass of water as  45.34% thus we can write;

45.34% = 12(H20)/2(X) + Fe + 6(CN)

Hence;

45.34/100 = 12(18)/2X + 56 + 6(26)

0.45 = 216/2X + 56 + 156

0.45 = 216/2X + 212

0.45(2X + 212) = 216

0.9X + 95.4 = 216

X = 216 -  95.4/0.9

X = 134

The element X from the calculation is Cs.

Learn more about formula of a compound:https://brainly.com/question/17291729

#SPJ1

Otras preguntas