The radius of a hydrogen atom is 5.29 × 10⁻¹¹ m. The electric force between the single proton and the single electron of a hydrogen atom is 7.94 × 10⁻⁸ N.
[tex]F = \frac{1}{4 \pi \epsilon_{0}} \cdot \frac{q_1 q_2}{r^2}[/tex]
where,
F = Electric Force
k = Coulomb constant
r = distance of separation
Now,
[tex]F = \frac{1}{4 \pi \epsilon_{0}} \cdot \frac{q_1 q_2}{r^2}[/tex]
[tex]= \frac{1}{4 \pi \epsilon_{0}} \cdot \frac{e^2}{r^2}[/tex]
[tex]= \frac{1}{4 \pi\ 8.85 \times 10^{-12}} \cdot (\frac{1.6 \times 10^{-19}}{5.29 \times 10^{-11}})^{2}[/tex]
= 7.94 × 10⁻⁸ N
Thus from the above conclusion we can say that The radius of a hydrogen atom is 5.29 × 10⁻¹¹ m. The electric force between the single proton and the single electron of a hydrogen atom is 7.94 × 10⁻⁸ N.
Learn more about the Coulomb's Law here: https://brainly.com/question/66110
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