The smallest of the even integers is 8.
It is a well-known fact that the sum of the first n odd numbers is n^2. This makes the sum of the first 8 odd numbers equal to 64.
Let n be equal to the smallest of the 5 even integers. Then (n+2) is the next highest, (n+4) even higher, and so on.
This sets up the equation n+(n+2)+(n+4)+(n+6)+(n+8)+4=64
Now we solve:
5n+24 = 64
5n = 40
n = 8
The smallest of the even integers is 8.
Learn more about integers here: https://brainly.com/question/14453211
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