1.5 mol is the theoretical yield of aluminum oxide if 3.00 mol of aluminum metal is exposed to 2.55 mol of oxygen.
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
2Al + [tex]\frac{3}{2}[/tex] O₂ → Al₂O₃
4Al + 3O₂ → 2 Al₂O₃ [Balanced Chemical Equation]
When aluminium is the limiting reagent then
3.00 × [tex]\frac{1}{2}[/tex] = 1.5 mol
When oxygen is the limiting reagent then
2.55 × [tex]\frac{2}{3}[/tex] = 1.70 mol
Thus from the above conclusion we can say that 1.5 mol is the theoretical yield of aluminum oxide if 3.00 mol of aluminum metal is exposed to 2.55 mol of oxygen.
Learn more about the Balanced Chemical equation here: https://brainly.com/question/26694427
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