The molecular formula of the compound is [tex]Cr_{2}S_{3}O_{12}[/tex].
Mass of Cr = 0.70 g
Mass of S = 0.65 g
Mass of O = 1.30 g
Molecular mass = 392.2 g
Moles of Cr = [tex]\frac{0.70}{52.0}[/tex]
= 0.01346 mol
Moles of S = [tex]\frac{0.65}{32.06}[/tex]
= 0.02025 mol
Moles of O = [tex]\frac{1.30}{16.0}[/tex]
= 0.08125 mol
Dividing both sides with lower quantity ;
[tex]Cr_{\frac{0.01346}{0.01346} } S_{\frac{0.2025}{0.01346} } O _{\frac{0.08125}{0.01346} }[/tex]≅ [tex]CS_{1.5} O_{6}[/tex]
And [tex](empirical formula )_{n} = molecular formula[/tex]
392.2 = n (52.0 + 6 × 16.0)
n = 2
Therefore, the molecular formula of the compound is [tex]Cr_{2}S_{3}O_{12}[/tex].
Learn more about molecular formula here:
https://brainly.com/question/13058832
#SPJ4
